Question

express x^2-8x in the form (x-a)^2-b where a and b are integers

Answer 1

Answer:

$(x-4)^{2} -16$

Step-by-step explanation:

$x^{2} -8x\\\frac{8}{2} =4\\4^{2} =16\\\\x^{2}-8x+16-16\\\\ (x-4)^{2} -16$