Answer:
Apparent frequency of the bell to the observer is 546.12 Hz
Explanation:
The frequency of train bell (frequency of source) = 505 Hz
The speed of train (observer) = 27.6 m/s
The speed of sound in the air is (velocity of sound) = 339 m/s
The apparent frequency of the bell to the observer is calculated as follows:
Apparent frequency of bell to the observer.
[tex]= \text{frequency of source} \times \frac{Observer + velocity \ of \ sound }{ velocity \ of \ sound } \\= 505 \times \frac{27.6 + 339}{339} \\= 546.12 Hz[/tex]