Answer:
[tex]0.79 in^3[/tex]
Step-by-step explanation:
Given data for the cone
height h= 4 in
radius r= 1 in
hence diameter d= 2 in
thickness of cone= 0.1 in
The volume of the cone including the shell can be expressed as
[tex]volume=\frac{1}{3} \pi r^2h[/tex]
[tex]volume= \frac{1}{3}*3.142*1^2*4\\\volume= \frac{12.568}{3} \\\volume= 4.189 in^3[/tex]
The volume of the ice cream can be expressed as
N/B: the diameter of the ice cream is
2-(0.1*2)= 2-0.2= 1.8 in
hence the radius is 0.9 in
[tex]volume= \frac{1}{3}*3.142*0.9^2*4\\\ volume= \frac{10.18}{3} \\\ volume= 3.39 in^3[/tex]
The difference in volume is [tex]4.189-3.39= 0.79 in^3[/tex]
