Respuesta :

Answer:

Option B.

Step-by-step explanation:

The given triangle is a right angle triangle.

In a right angle triangle,

[tex]\tan \theta=\dfrac{Perpendicular}{Base}[/tex]

In the given triangle,

[tex]\tan (30^{\circ})=\dfrac{n}{\sqrt{3}}[/tex]

[tex]\dfrac{1}{\sqrt{3}}=\dfrac{n}{\sqrt{3}}[/tex]

[tex]1=n[/tex]

Using Pythagoras theorem, we get

[tex]hypotenuse^2=Perpendicular^2+Base^2[/tex]

[tex]m^2=n^2+(\sqrt{3})^2[/tex]

[tex]m^2=1^2+3[/tex]

[tex]m^2=4[/tex]

Taking square root on both sides, we get

[tex]m=\sqrt{4}[/tex]

[tex]m=2[/tex]

Therefore, the correct option is B.

ACCESS MORE