Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized,
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Answer:
Option B.
Step-by-step explanation:
The given triangle is a right angle triangle.
In a right angle triangle,
[tex]\tan \theta=\dfrac{Perpendicular}{Base}[/tex]
In the given triangle,
[tex]\tan (30^{\circ})=\dfrac{n}{\sqrt{3}}[/tex]
[tex]\dfrac{1}{\sqrt{3}}=\dfrac{n}{\sqrt{3}}[/tex]
[tex]1=n[/tex]
Using Pythagoras theorem, we get
[tex]hypotenuse^2=Perpendicular^2+Base^2[/tex]
[tex]m^2=n^2+(\sqrt{3})^2[/tex]
[tex]m^2=1^2+3[/tex]
[tex]m^2=4[/tex]
Taking square root on both sides, we get
[tex]m=\sqrt{4}[/tex]
[tex]m=2[/tex]
Therefore, the correct option is B.