Question

An 100 V/m electric field is directed along the x axis. If the potential at the origin is 300 V, what is potential at the point ( -2m, 0) point

Answer 1

Answer:

200volts

Explanation:

Pls see attached file

Answer 2

Answer:

100 V

Explanation:

Electric field E = 100 V/m

Potential at the origin = 300 V

Potential at point (-2m, 0) i.e 2 m behind the origin = ?

From the equation ΔV = EΔd,

ΔV = $V_{0} - V_{x}$

where $V_{0}$ is the potential at origin,

and $V_{x}$ is the potential at point (-2, 0)

E = electric field

Δd = 0 - (-2) = 2 m

$V_{0} - V_{x}$ = 300 - $x$

equating, we have

 300 - $x$ = 100 x 2

300 - $x$ = 200

$x$ = 100 V