If a ball is thrown into the air with a velocity of 43 ft/s, its height (in feet) after t seconds is given by y = 43t - 16t^2. Find the velocity when t = 2.
Let h = s(t) = 50t − 16t2 give the height of the ball at time t. Then the ball's velocity at time t = a can be found by v(a) = lim t→a s(t) − s(a) t
