Answer:
Therefore, the slope-intercept form of the blue line is
[tex]y = \frac{1 }{2}x + 2[/tex]
Comparison:
The blue and black lines both have equal y-intercept but different slopes.
The black line is steeper than blue line which means the black line has a greater slope than the blue line.
Step-by-step explanation:
Please refer to the attached graph of this question where we have two straight lines.
The slope-intercept form is given by
[tex]y = mx + b[/tex]
Where m is the slope of the line and b is the y-intercept.
Let us find the slope of the blue line from the points given in the graph.
[tex](x_1, y_1) = (0,2) \\\\(x_2, y_2) = (4,4) \\\\[/tex]
The slope is given by
[tex]m = \frac{y_2 -y_1 }{x_2 -x_1} \\\\m = \frac{4 -2 }{4 -0} \\\\m = \frac{2 }{4} \\\\m = \frac{1 }{2} \\\\[/tex]
The y-intercept is given by
[tex]y = \frac{1 }{2}x + b \\\\2 = \frac{1 }{2}(0) + b \\\\b = 2[/tex]
Therefore, the slope-intercept form of the blue line is
[tex]y = \frac{1 }{2}x + 2[/tex]
Comparison:
The blue and black lines both have equal y-intercept but different slopes.
The black line is steeper than blue line which means the black line has a greater slope than the blue line.