Respuesta :
Answer:
The area of EFGH is always One-half of the area of the rectangle.
Step-by-step explanation:
If F and H are midpoints of sides of rectangle then FH is parallel to the other side of rectangle so FH is perpendicular to the EG. That means the lenght of FH is equal to lenght of rectangle, and the lenght of EG is equal to width of rectangle.
So the area of the rectangle: [tex]A_{rectangle}=EG\cdot FH[/tex]
FH ⊥ EG so the area of quadrangle EFGH:
[tex]A_{_{EFGH}}=\frac12EG\cdot FH=\frac12A_{rectangle}[/tex]
no matter the location of segment EG