Question

Factor completely 2x2 − 2x − 40. 2(x − 5)(x + 4) (2x − 10)(x + 4) (x − 5)(2x + 8) 2(x − 4)(x + 5)

Answer 1

Answer:

$2(x + 4)(x - 5)$

Step-by-step explanation:

Given

$2x^2 - 2x - 40$

Required

Factorize

$2x^2 - 2x - 40$

Start by expanding the above expression

$2x^2 - 10x + 8x- 40$

Then, split the expanded expression into two

$(2x^2 - 10x) + (8x- 40)$

Factorize the split expression:

$2x(x - 5) + 8(x- 5)$

$(2x + 8)(x - 5)$

Expand the expression in the first bracket

$(2x + 2*4)(x - 5)$

Then take out common factor

$2(x + 4)(x - 5)$

From the list of given options, option A is correct

Answer 2

Answer:

A

Step-by-step explanation:

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