Given that,
Mass of truck = 1000 kg
Speed = 108 km/h = 30 m/s
Distance = 10 m
We need to calculate the acceleration
Using equation of motion
[tex]v^2=u^2+2as[/tex]
Where, v = final speed
u = initial speed
s = distance
Put the value into the formula
[tex](0)^2=30^2+2\times a\times 10[/tex]
[tex]a=-\dfrac{30^2}{2\times10}[/tex]
[tex]a= -45 m/s^2[/tex]
We need to calculate the magnitude of the frictional force acting on the truck
Using formula of force
[tex]F=ma[/tex]
Where, m = mass of truck
a = acceleration
Put the value into the formula
[tex]F=1000\times(-45)[/tex]
[tex]F= -45000\ N[/tex]
Negative sign shows the opposite direction of motion.
Hence, The magnitude of the frictional force acting on the truck is 45000 N.