Answer:
model: [tex]P(t) = 399 * (0.5)^t[/tex]
amount after 6 days: [tex]P(6) = 6.2344\ grams[/tex]
Step-by-step explanation:
We can use the exponencial function of growth/decay to model this problem:
[tex]P(t) = Po * (1 + r)^t[/tex]
Where P(t) is the final value after time t, Po is the inicial value and r is the rate of change.
In our case, the inicial value is 399 grams, the rate is -0.5 (that is, the value decreases by half in each time cycle), and t is the time in days.
So our function will be:
[tex]P(t) = 399 * (0.5)^t[/tex]
Then, to find the amount of substance after 6 days, we just need to calculate P using t = 6:
[tex]P(6) = 399 * (0.5)^6[/tex]
[tex]P(6) = 6.2344\ grams[/tex]