Respuesta :
Answer:
ΔAKL is congruent to ΔBML by the Side Angle Side rule of congruency and ΔALB is isosceles as two of its sides [tex]\overline {AL}[/tex] and [tex]\overline {BL}[/tex] are congruent
Step-by-step explanation:
The given parameters are;
The given triangle ΔKLM has sides [tex]\overline {KL}[/tex] ≅ [tex]\overline {LM}[/tex], Given
ΔKLM is isosceles Δ (two equal segments), Definition of isosceles Δ
∠LKM ≅ ∠LMK, Base ∠s of isosceles Δ are ≅
Point A is on segment [tex]\overline {KM}[/tex], Given
Point B is also on segment [tex]\overline {KM}[/tex], Given
Segment [tex]\overline {AK}[/tex] ≅ segment [tex]\overline {BM}[/tex], Given
ΔAKL ≅ ΔBML, SAS rule of congruency
Segment [tex]\overline {AL}[/tex] ≅ segment [tex]\overline {BL}[/tex], CPCTC
ΔALB is isosceles (two equal segments), Definition of isosceles Δ
Where:
SAS = Side Angle Side
CPCTC = Congruent parts of congruent triangles are congruent.
Answer:
m∠AKL=m∠BML | Base Angle Theorem (Base ∠ TH.)
Step-by-step explanation:
KL=LM | Given
A ∈ KM | Given
B ∈ KM | Given
AK=BM | Given
m∠AKL=m∠BML | Base ∠ TH.
