Question

in the interval 0 x 360 find the values of x for which cos x =0.7252

Answer 1

Answer:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

Step-by-step explanation:

We have a positive value for the cosine of x, so we know that the value of x should be in the first quadrant (0 ≤ x ≤ 90) or in the fourth quadrant (270 ≤ x ≤ 360).

Now, let's find the value of x that gives cos(x) = 0.7252 using the inverse function of the cosine, that is, the arc cosine function.

The value of x can be calculated using:

$x = arccos(0.7252)$

Using this function in a calculator (you may find it as: $cos^{-1}(x)$), we have that:

$x_1 = 43.5145\°$

So this is the value of x in the first quadrant. To find the other value of x, in the fourth quadrant, that gives the same result, we just need to calculate 360° minus the value we found:

$x_2 = 360\° - 43.5145\° = 316.4855\°$

So the values of x are:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$