Question

what must be added to
15x²-10x to make it
perfect square
a​

Answer 1

Answer:

Step-by-step explanation:

hello,

$15x^2-10x=15(x^2-\dfrac{10}{15}x)=15(x^2-\dfrac{2}{3}x)$

and we can write that

$(x-\dfrac{2}{2*3})^2=(x-\dfrac{1}{3})^2=x^2-\dfrac{2}{3}x+\dfrac{1}{9}$

so

$x^2-\dfrac{2}{3}x= (x-\dfrac{1}{3})^2-\dfrac{1}{9} \ so\\15x^2-10x=15(x^2-\dfrac{2}{3}x)=15[(x-\dfrac{1}{3})^2-\dfrac{1}{9} ]=15(x-\dfrac{1}{3})^2-\dfrac{15}{9}\\=15(x-\dfrac{1}{3})^2-\dfrac{5}{3}$

Then

$15x^2-10x+\dfrac{5}{3}=15(x-\dfrac{1}{3})^2$

then, I would say that you need to add 5/3 to make a perfect square

hope this helps

Answer 2

Bhaad mein jaaa gadhe