In order for the parallelogram to
be a square, x=?
![In order for the parallelogram to be a square x class=](https://us-static.z-dn.net/files/d43/3a44d3b998e663ec8c4655d9823a164f.png)
Answer:
Step by step explanation
We know that the diagonals of a square bisects it's angles and every angles of square are 90°
m<BCD = 90°
m<BCA = m< DCA = 4x + 17
m<BCA + m<DCA = m <BCD
4x + 17 + 4x + 17 = 90
4x + 4x + 17 + 17 = 90
8x + 34 = 90
8x = 90 - 34
8x = 56
X = 56/8
x = 7
Hope this helps...
Good luck on your assignment...
In square, the angle between the diagonal and the sides of the square is 45°. Then the value of x is 15.5°.
What is a square?
It is a polygon with four sides. The total interior angle is 360 degrees. In a square, opposite sides are parallel, all side are equal, and each angle is 90 degrees.
In square, the angle between the diagonal and the sides of the square is 45°.
4x + 17° = 45°
4x = 62°
x = 15.5°
More about the square link is given below.
https://brainly.com/question/13747846
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