Question

the ellipse is centered at the origin, has axes of lengths 8 and 4, its major axis is horizontal. how do you write an equation for this ellipse?​

Answer 1

Answer:

The equation for this ellipse is $\frac{x^{2}}{64} + \frac{y^{2}}{16} = 1$.

Step-by-step explanation:

The standard equation of the ellipse is described by the following expression:

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}} = 1$

Where $a$ and $b$ are the horizontal and vertical semi-axes, respectively. Given that major semi-axis is horizontal, $a > b$. Then, the equation for this ellipse is written in this way: (a = 8, b = 4)

$\frac{x^{2}}{64} + \frac{y^{2}}{16} = 1$

The equation for this ellipse is $\frac{x^{2}}{64} + \frac{y^{2}}{16} = 1$.