Use back-substitution to solve the system of linear equations.
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Step-by-step explanation:
x - y + 5z = 29
y + 2z = 4
z = 7
since z = 7 we can use this value in second equation
y + 2×7 = 4 and y = -10
now we know the value of y we can solve the first equation
x -(-10) + 5×7 = 29
x + 10 + 35 = 29
x = -11