Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120°. Which equation should you solve to find the length of the third side of the triangle?

Suppose a triangle has two sides of length 42 and 35 and that the angle between these two sides is 120 Which equation should you solve to find the length of the class=

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Answer:

D is the correct answers

Step-by-step explanation:

If we know two sides and an included angle of any triangle, we can use law of cosines to find the unknown length of the third side

The correct option is D. [tex]c^{2} =(42)^{2} +(35)^{2} -2(35)(42)cos120[/tex].

Given  triangle has two sides of length 42 and 35, and angle between these two sides is 120°.

The Law of Cosines is used to find the remaining parts of an oblique (non-right) triangle when either the lengths of two sides and the measure of the included angle is known (S A S) or the lengths of the three sides (SSS) are known.

From this law ,we have [tex]a^{2} =b^{2} +c^{2} -2 bc cos \alpha[/tex] , here a is the length of side to be calculated and alpha is the angle between the known side.

So,here  [tex]a^{2} =(42)^{2} +(35)^{2} -2(42)(35) cos120[/tex], since angle between the known sides is 120°.

Hence the correct option is D. [tex]c^{2} =(42)^{2} +(35)^{2} -2(35)(42)cos120[/tex].

For more details on Law of cosine follow the link:

https://brainly.com/question/17289163