Explanation:
velocity of a freely falling body is given as
[tex]v= \sqrt{2gh}[/tex]
h= height and g= acc. due to gravity = 32ft/sec^2.
now, t secs the object at height of s feet its velocity
[tex]s=ut +gt^2[/tex]
here u= initial velocity =0,
therefore,
[tex]s=gt^2[/tex]