Question

What is the discriminant of the quadratic equation 3 – 4x = –6x2? –68 –56 76 88

Answer 1

Answer:

The answer is option 2.

Step-by-step explanation:

First, you have to make the equation into 0, by adding 6x² to both sides :

$3 - 4x = - 6 {x}^{2}$

$3 - 4x + 6 {x}^{2} = - 6 {x}^{2} + 6 {x}^{2}$

$6 {x}^{2} - 4x + 3 = 0$

Next, you have to apply Discriminant formula, D = b² - 4ac. Given that a quadratic equation is ax² + bx + c = 0, so for this equation a represents 6, b is -4 and c is 3 :

$D = {b}^{2} - 4ac$

$let \: a = 6 \\ let \: b = - 4 \\ let \: c = 3$

$D = {( - 4)}^{2} - 4(6)(3)$

$D = 16 - 72$

$D = - 56$

Answer 2

Answer:

-56.

Step-by-step explanation:

3 – 4x = –6x^2

6x^2 - 4x + 3 = 0

The discriminant is simply b^2 - 4ac. In this case, a = 6, b = -4, and c = 3.

(-4)^2 - 4 * 6 * 3 = 16 - (24 * 3) = 16 - 72 = -56

Hope this helps!