Answer:
- a = -3
- b = 5/2
- c = -1/2
Step-by-step explanation:
[tex]3^a = 1/27\\Write ; 1/27 -in-exponential-form\\3^a = 3^-^3\\Cancel-out-the-base\\a = -3[/tex]
[tex]3^b = 9\sqrt{3} \\Convert 9\sqrt{3} to base 3\\ 3^b = 3^{\frac{5}{2} } \\Cancel-out-the-base\\b = 5/2[/tex]
[tex]3^c = \frac{1}{\sqrt{3} } \\Apply -exponent -rule ;\frac{1}{a^b}=a^{-b}\\\frac{1}{\sqrt{3}}=3^{-\frac{1}{2}}\\3^c = 3^{-\frac{1}{2} } \\\mathrm{Apply\:exponent\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}\\3^{-\frac{1}{2}}=3^{-\frac{1}{2}}\\3^c = 3^{-\frac{1}{2} } \\\mathrm{If\:}a^{f\left(x\right)}=a^{g\left(x\right)}\mathrm{,\:then\:}f\left(x\right)=g\left(x\right)\\c = -\frac{1}{2}[/tex]
Hey there,
Are you in need of a Math homework help or do you happen to know anyone who does?
If yes , contact me on Hangouts .
My email address is ; zephaniahjshammah (at symbol) gma il . com
