Answer:
the final mole of the flexible container = 12.92 moles
Explanation:
Given that :
initial volume of a flexible container = 6.13 L
initial mole of a flexible container = 6.51 mol
final volume of a flexible container = 18.3 L
final mole of a flexible container = ???
Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Therefore,
[tex]n= \dfrac{V_2*n_1}{V_1}[/tex]
[tex]n= \dfrac{18.3*6.51}{6.13}[/tex]
n = 19.43
[tex]n=n_1+n_2[/tex]
19.43 = 6.51 + n₂
n₂ = 19.43 - 6.51
n₂ = 12.92 moles
Thus; the final mole of the flexible container = 12.92 moles