When p = 12, t = 2, and s = One-sixth, r = 18. If r varies directly with p and inversely with the product of s and t, what is the constant of variation?

Respuesta :

Answer:

[tex]k = \frac{1}{2}[/tex]

Step-by-step explanation:

Given

[tex]p = 12[/tex]

[tex]t = 2[/tex]

[tex]s = \frac{1}{6}[/tex]

[tex]r = 18[/tex]

[tex]r\ \alpha\ p\ * \frac{1}{s * t}[/tex]

Required

Find the constant of variation

From the question, the variation is as follows

[tex]r\ \alpha\ p\ * \frac{1}{s * t}[/tex]

[tex]r\ \alpha\ \frac{p * 1}{s * t}[/tex]

[tex]r\ \alpha\ \frac{p}{s * t}[/tex]

Convert variation to equation

[tex]r\ = k\frac{p}{s * t}[/tex]

Where k represents the constant of variation

Make k the subject of formula;

Multiply both sides by s * t

[tex]r * s * t = k\frac{p}{s * t} * s * t[/tex]

[tex]r * s * t = kp[/tex]

Divide both sides by p

[tex]\frac{r * s * t}{p} = \frac{kp}{p}[/tex]

[tex]\frac{r * s * t}{p} = k[/tex]

[tex]k = \frac{r * s * t}{p}[/tex]

Substitute the values of p, r, s and t in the above equation

[tex]k = \frac{18 * \frac{1}{6} * 2}{12}[/tex]

[tex]k = \frac{6}{12}[/tex]

Divide numerator and denominator by 6

[tex]k = \frac{1}{2}[/tex]

Hence, the constant of variation is; [tex]k = \frac{1}{2}[/tex]

Answer:

b

Step-by-step explanation:

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