Answer:
79%
Explanation:
The following data were obtained from the question:
Input temperature = 100°C
Output temperature = 22°C
Efficiency =.?
Next, we shall convert the temperature from celsius to Kelvin temperature. This is illustrated below:
T (K) = T (°C) + 273
Input temperature = 100°C
Input temperature = 100°C + 273 = 373K
Output temperature = 22°C
Output temperature = 22°C + 273 = 295K
The efficiency of the locomotive can be obtained as follow:
Input temperature = 373K
Output temperature = 295K
Efficiency =.?
Efficiency = output /input x 100
Efficiency = 295/373 x 100
Efficiency = 79%
Therefore, the efficiency of the locomotive is 79%.
