Question

Suppose that in a particular country, the probability that a randomly chosen person is a left-handed baseball player is 0.0150.015 and the probability that a randomly chosen baseball player is left-handed is 0.240.0.240. Based on these probabilities, determine the probability, p,p, that a randomly chosen person from this country plays baseball. Give your answer as a decimal precise to at least three decimal places.

Answer 1

Answer:

0.0625

Step-by-step explanation:

Given:

P(left-handed person is a baseball player ) = 0.015

P(baseball player is a lefthanded person) = 0.240

Required:

Find the probability, that a randomly chosen person from this country plays baseball.

Let,

A =  event of being a baseball player

B = event of player being left handed.

Therefore,

P(A and B) = 0.015

P(B|A) = 0.240

To find the probability, that a randomly chosen person from this country plays baseball, use the formula:

P(A) = P(A and B) / P(B|A)

Thus,

$P(A) = \frac{0.015}{0.240}$

$P(A) = 0.0625$

Therefore

The probability, that a randomly chosen person from this country plays baseball is 0.0625