Please help again! Same thing!
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Answer:
a = - 3, b = 5
Step-by-step explanation:
To rationalise the denominator multiply the numerator/ denominator by [tex]\sqrt{2}[/tex]
= [tex]\frac{\sqrt{2}(10-\sqrt{18}) }{(\sqrt{2})^2 }[/tex]
= [tex]\frac{10\sqrt{2}-\sqrt{36} }{2}[/tex]
= [tex]\frac{10\sqrt{2}-6 }{2}[/tex]
= 5[tex]\sqrt{2}[/tex] - 3
= - 3 + 5[tex]\sqrt{2}[/tex] ← in the form a + b[tex]\sqrt{2}[/tex]
with a = - 3 and b = 5