Question

Please help urgently!

Answer 1

Answer:

$a=-6\quad and \quad b=8$

Step-by-step explanation:

$\frac{8-\sqrt{18}}{\sqrt{2}}=\frac{\sqrt{2}}{\sqrt{2}}\times \frac{8-\sqrt{18}}{\sqrt{2}}\\\\=8\sqrt{2}-\sqrt{2}\cdot \sqrt{18}\\\\=8\sqrt{2}-\sqrt{36}\\\\=-6+8\sqrt2$

By comparing the last expression with  $a+b\sqrt{2}$, we get:

$a=-6\quad and \quad b=8$

Best Regards!

Answer 2

For a: a = 4√2 - 3 - b √2

For b: b = ( 4√2 - 3 - a )√ 2 / 2