To the nearest tenth, which is the perimeter of ABC. Geometry
![To the nearest tenth which is the perimeter of ABC Geometry class=](https://us-static.z-dn.net/files/da4/e04aed5b8d0034d5a1ea5b644900327e.png)
Answer:
23.6
Step-by-step explanation:
Finding AC:
Cos 61 = [tex]\frac{adjacent}{hypotenuse}[/tex]
0.48 × 10 = Adjacent
AC = 4.8
Now, CB:
Cos 29 = [tex]\frac{adjacent}{hypotenuse}[/tex]
0.87 × 10 = CB
CB = 8.8
The perimeter:
=> 10+4.8+8.8
=> 23.6