Question

$\sqrt{-16} -\sqrt{-3} \sqrt{-3} -\sqrt{-4} \sqrt{-4} +3i-3i^{2} +3i^3$

Answer 1

Answer:

4(i-1)

Step-by-step explanation:

Given the expression   $\sqrt{-16} - \sqrt{-3} \sqrt{-3} -\sqrt{-4} \sqrt{-4}+3i-3i^{2} +3i^{3}$

On simplifying;

First we need to note that i² = -1 and √-1 = i

Substituting the values in the expression, it becomes;

= √16(√-1)-√(-3)(-3)-√(-4)(-4)+3i-3(-1)+3i(i²)

= 4i-√9-√16+3i+3-3i

= 4i-3-4+3

= 4i-4

= 4(i-1)