Answer:
4.35 mol/L
Explanation:
There is some info missing. I think this is the original question.
A chemist prepares a solution of sodium chloride by measuring out 25.4 grams of sodium chloride into a 100 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.
Step 1: Calculate the moles of sodium chloride
The molar mass of sodium chloride is 58.44 g/mol. The moles corresponding to 25.4 grams of sodium chloride are:
[tex]25.4g \times \frac{1mol}{58.44g} = 0.435mol[/tex]
Step 2: Calculate the liters of solution
We will use the relationship 1 L = 1,000 mL.
[tex]100mL \times \frac{1L}{1,000mL} = 0.100L[/tex]
Step 3: Calculate the concentration of sodium chloride in mol/L
[tex]\frac{0.435mol}{0.100L} =4.35 mol/L[/tex]