Answer:
K = 109.1 N/m
Explanation:
From the question, the following parameters are given.
Extension e = 55 m
Force F = 6000N
According to Hooke's law,
F = Ke
Where K = spring constant.
Substitute F and e into the formula and make K the subject of formula.
6000 = K × 55
K = 6000/55
K = 109.1 N/m
Therefore, the spring constant of a bungee cord that stretches is 109.1 N/m
