Question

- find the general term of the sequence 1,-1,1-1​

Answer 1

Answer:

The general term of the sequence is

${ - 1}^{n - 1}$

Step-by-step explanation:

The sequence above is a geometric sequence

For an nth term in a geometric sequence

$u(n) = a(r) ^{n - 1}$

Where n is the number of terms

a is the first term

r is the common ratio

From the above sequence

a = 1

r = -1/1 = -1

The nth term of the sequence is

$u(n) = 1 ({ - 1})^{n - 1} \\ = { - 1}^{n - 1}$

Hope this helps you