Question

A disk between vertebrae in the spine is subjected to a shearing force of 640 N. Find its shear deformation taking it to have the shear modulus of 1.00 109 N/m2. The disk is equivalent to a solid cylinder 0.700 cm high and 4.30 cm in diameter.

Answer 1

Answer:

3.08*10^-6 m

Explanation:

Given that

Total shearing force, F = 640 N

Shear modulus, S = 1*10^9 N/m²

Height of the cylinder, L = 0.7 cm

Diameter of the cylinder, d = 4.3 cm

The solution is attached below.

We have our shear deformation to be 3.08*10^-6 m