Question

Write the equation of the line perpendicular to y= 5/4x+9/4
that passes through the point (-8,7). Write the equation using slope-intercept form or using the given in point-slope form.

Answer 1

Answer:

$x = \frac{4y - 9}{5}$

$\frac{5}{4x} + \frac{9}{4} = y \\ \frac{5}{4x} = y - \frac{9}{4} \\ \frac{5}{4} over \frac{5}{4x} = \frac{y - \frac{9}{4} }{5 \frac{}{4} } \\ x = \frac{4y - 9}{5}$

Answer 2

Answer:

Step-by-step explanation:

$y= 5/4x+9/4\\ (-8,7).\\\\m = \frac{5}{4} \\\\Perpendicular =m= \frac{1}{m2}\\\ 5/4 = -4/5\\substitute : (-8,7)-into slope -intercept -form\\ \\y =mx+b\\7=\frac{-4}{5}(-8)+b\\\\7 = \frac{32}{5} +b\\\\b=7-32/5\\b = 3/5\\m =-4/5\\substitute-into-slope-intercept-form\\y = mx+b\\y = -\frac{4}{5} x+\frac{3}{5}$