Respuesta :

Answer:

second option

Step-by-step explanation:

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

Simplifying the radicals

[tex]\sqrt{27x^{3} }[/tex]

= [tex]\sqrt{9(3)x^2.x}[/tex]

= [tex]\sqrt{9}[/tex] × [tex]\sqrt{3}[/tex] × [tex]\sqrt{x^2}[/tex] × [tex]\sqrt{x}[/tex]

= 3 × [tex]\sqrt{3}[/tex] × x × [tex]\sqrt{x}[/tex]

= 3x[tex]\sqrt{3x}[/tex]

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[tex]\sqrt{12x^{3} }[/tex]

= [tex]\sqrt{4(3)x^2.x}[/tex]

= [tex]\sqrt{4}[/tex] × [tex]\sqrt{3}[/tex] × [tex]\sqrt{x^2}[/tex] × [tex]\sqrt{x}[/tex]

= 2 × [tex]\sqrt{3}[/tex] × x × [tex]\sqrt{x}[/tex]

= 2x[tex]\sqrt{3x}[/tex]

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Thus

3 × 3x[tex]\sqrt{3x}[/tex] - 2 × 2x[tex]\sqrt{3x}[/tex]

= 9x[tex]\sqrt{3x}[/tex] - 4x[tex]\sqrt{3x}[/tex]

= 5x[tex]\sqrt{3x}[/tex]

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