Question

Select the correct answer. What are the solutions to this quadratic equation?
A)x=4+sqrt 10
B)x=-2+4 sqrt 10
C)x=4+2 sqrt 10
D)x=-4+4 sqrt 10

Answer 1

Answer:

Let's solve your equation

$x^2+13=8x+37$

Step 1: Subtract 8x+37 from both sides.

$x^2+13-(8x+37)=8x+37-(8x+37)$

$x^2-8x-24=0$

For this equation: a= 1, b= -8, c= -24

Step 2: Use quadratic formula with a=1, b=-8, c=-24.

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-8)+\sqrt{(-8)^2-4(1)(-24)} }{2(1)}$

$x=\frac{8+\sqrt{160} }{2}$

$x=4+2\sqrt{10}$   or  $x=4-2\sqrt{10}$       This is the answer

So,the correct option is C

I hope this help :)