Question

Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 degrees. Trigonometric area formula: Area = One-half a b sine (C) What is the area of triangle PQR? Round to the nearest tenth of a square unit.

Answer 1

Answer:

112.3 square units

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = $\frac{1}{2}|PQ| |PR| sinQPR$

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)

Answer 2

Answer:

111.3

Step-by-step explanation: