Answer: [tex]\bold{\dfrac{4x-5}{x-2}}[/tex]
Step-by-step explanation:
Since the expressions have the same denominator, we simply need to add the numerators.
[tex]\dfrac{x+3}{x-2}+\dfrac{3x-8}{x-2}\quad =\quad \dfrac{x+3+3x-8}{x-2}\quad = \quad \large\boxed{\dfrac{4x-5}{x-2}}[/tex]
