Question

Applying the recursive rule aₙ; a ₙ ₋ ₁ + 3, write the first seven (7) terms of the sequence when a = 10.

Answer 1

Answer:

First seven terms apart from 10 are

13, 16, 19, 22, 25, 28, 31

Step-by-step explanation:

Given recursive rule aₙ = a ₙ ₋ ₁ + 3

a1 = 10

$x_{1} = 10\\x_{2} = x_{2-1} + 3= x_{1} + 3 = 10 + 3 = 13\\x_{3} = x_{3-1} + 3= x_{2} + 3 = 13 + 3 = 16\\x_{4} = x_{4-1} + 3= x_{3} + 3 = 16 + 3 = 19\\x_{5} = x_{5-1} + 3= x_{4} + 3 = 19 + 3 = 22\\x_{6} = x_{6-1} + 3= x_{5} + 3 = 22 + 3 = 25\\\x_{7} = x_{7-1} + 3= x_{6} + 3 = 25 + 3 = 28\\x_{8} = x_{8-1} + 3= x_{7} + 3 = 28 + 3 = 31$

Thus, first seven terms apart from 10 are

13, 16, 19, 22, 25, 28, 31