Question

Find the equation of the straight line passing through the point (0, 1)
which is perpendicular to the line
y = -2x + 2
:)

Answer 1

Answer:

$y = \frac{1}{2} x+1$

Step-by-step explanation:

Perpendicular => So, it will have a slope of a negative reciprocal to this slope

Slope = m = 1/2

Now,

Point = (x,y) = (0,1)

So, x = 0 and y = 1

Putting this in slope-intercept equation to get b

=> $y = mx+b$

=> 1 = (1/2)(0) + b

=> b = 1

Now putting m and b in the slope intercept equation to get the required equation

=> $y = \frac{1}{2} x+1$

Answer 2

Answer:

y = \frac{1}{2} x+1

Step-by-step explanation: