Respuesta :
Answer:
0.043 m
Explanation:
From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.
The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³
If we assume pressure at the two points to be the same, then
P1 = P2
ρ1.g.V1 = ρ2.g.V2
ρ1.A.h1 = ρ2.A.h2
ρ1.h1 = ρ2.h2, making h1 subject of formula
h1 = ρ2.h2 / ρ1, so that
h1 = 790 * 0.25 / 1260
h1 = 197.5 / 1260
h1 = 0.157 m
Δh = 0.2 - 0.157
Δh = 0.043 m or 4.3 cm

The difference in height between the top surface of glycerin and the top surface of ethyl alcohol is 0.0432 meter or 4.32 centimeter.
Given the following data:
- Height of ethyl alcohol = 25 cm to m = 0.25 m
- Hydrostatic height = 20 cm to m = 0.2 m.
Scientific data:
- Density of ethyl alcohol = 790 [tex]kg/m^3[/tex]
- Density of glycerin = 1260 [tex]kg/m^3[/tex]
To calculate the difference in height between the top surface of glycerin and the top surface of ethyl alcohol:
The formula for hydrostatic pressure.
Mathematically, hydrostatic pressure is given by this formula:
[tex]P = \rho gh[/tex]
Where:
- [tex]\rho[/tex] is the density.
- g is the acceleration due to gravity.
- h is the height.
At constant temperature, the pressure at the top surface of glycerin in the open U-shaped tube is equal to the pressure at the top surface of ethyl alcohol:
[tex]\rho_{g}h_{g} = \rho_{a}h_{a}[/tex]
Substituting the given parameters into the formula, we have;
[tex]1260h_{g}=790 \times 0.25\\\\1260h_{g}=197.5\\\\h_{g} =\frac{197.5}{1260}[/tex]
Height of glycerin = 0.1568 meters.
Now, we can find the difference in height:
[tex]Difference = 0.2 - 0.1568[/tex]
Difference = 0.0432 meter or 4.32 centimeter.
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