Question

At which values of x does the function F(x) have a vertical asymptote? Check
all that apply,
F(x)
9
(x - 1)(x-8)

Answer 1

Answer:

The values of x that makes f(x) have a valid asymptote are 1 and 8

Step-by-step explanation:

Given

$f(x) = \frac{9}{(x-1)(x-8)}$

Required

At what value does f(x) has a vertical asymptote

To solve this, we simply equate the denominator of f(x) to 0;

This is done as follows

${(x-1)(x-8)} = 0$

This can be split to

${(x-1) = 0 \ or\ (x-8)} = 0$

Remove brackets

$x-1 = 0 \ or\ x-8 = 0$

Make x the subject of formula in both cases

$x-1+1 = 0+1 \ or\ x-8+8 = 0+8$

$x= 0+1 \ or\ x = 0+8$

$x= 1 \ or\ x = 8$

The values of x that makes f(x) have a valid asymptote are 1 and 8

Answer 2

Answer:

The correct answer is 1 and 8

Step-by-step explanation: