Question

2x + 4y = 12 y = A system of equations. 2 x plus 4 y equals 12. y equals StartFraction one-fourth EndFraction x minus 3.x – 3 What is the solution to the system of equations? (–1, 8) (8, –1) (5, StartFraction one-half EndFraction) (StartFraction one-half EndFraction, 5)

Answer 1

Answer:

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Step-by-step explanation:

x=8 and y=−1

so : (8,-1)

Answer 2

From the system of equation 2x + 4y = 12 and  y equals StartFraction one-fourth EndFraction x minus 3. The solution to the system of equations in terms of (x, y) is equal to ( (8, -1)

The system of equations is given as:

2x + 4y = 12        -------  (1)

$\mathbf{y = \dfrac{1}{4}x - 3} \ \ \ ----(2)$

So, from equation (1), we will replace the value of y which is $\mathbf{ \dfrac{1}{4}x - 3} }$ in order to be able to solve for x.

i.e.

$\mathbf{2x + 4\Big ( \dfrac{1}{4}x -3 \Big) = 12 }$

Open brackets

2x + x -12  = 12

3x - 12 = 12

3x = 12 + 12

3x = 24

x = 24/3

x = 8

Now, we will replace the value of x into equation (2) to be able to solve for y.

$\mathbf{y = \dfrac{1}{4}(8) - 3} }$

y = 2 -3

y = -1

Therefore, the solution to the system of equations in terms of (x, y) is equal to ( (8, -1)

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