Respuesta :
Answer:
(1)$68.02
(2)
a.) [tex]P(x\geq 2)=0.76[/tex]
b.) [tex]P(x\geq 3)=0.5[/tex]
c.) [tex]P(x> 3)=0.38[/tex]
d.) [tex]P(x< 2)=0.24[/tex]
e.) [tex]P(x\leq 2)=0.5[/tex]
f)[tex]\mu=2.72[/tex]
g)[tex]\sigma=1.33[/tex]
Step-by-step explanation:
Question 1
The probability distribution table for the average price of the textbook sales in each of these three time periods is given below:
[tex]\left|\begin{array}{c|c|c|c}&$Start-of-term&$End-of-term&$Other\\$Sales proportion&0.45&0.31&0.24\\$Average price&\$82.52&\$49.12&\$65.23\end{array}\right|[/tex]
We are required to calculate the average price of the textbook over all seasons.
Expected Value
[tex]= (0.45 X 82.52)+(0.31 X 49.12) +(0.24 X 65.23)\\=68.02[/tex]
The average price of the textbook over all seasons is $68.02
Question 2
Distribution Table for Number of Courses being taken by BHCC Students
[tex]\left|\begin{array}{c|ccccc}x$(No of classes)& 1&2&3 &4&5\\P(x)&0.24&0.26&0.12&0.3 &0.08\end{array}\right|[/tex]
a.) Probability that a student is taking 2 or more classes
[tex]P(x\geq 2)=0.26+0.12+0.3+0.08=0.76[/tex]
b.) Probability that a student is taking at least 3 classes
[tex]P(x\geq 3)=0.12+0.3+0.08=0.5[/tex]
c.) Probability that a student is taking more than 3 classes
[tex]P(x> 3)=0.3+0.08=0.38[/tex]
d.) Probability that a student is taking less than 2 classes
[tex]P(x< 2)=0.24[/tex]
e.) Probability that a student is taking no more than 2 classes
[tex]P(x\leq 2)=0.24+0.26=0.5[/tex]
f)Average (mean) amount of classes
[tex]=(1*0.24)+(2*0.26)+(3*0.12)+(4*0.3)+(5*0.08)\\\mu=2.72[/tex]
g)Standard deviation for the amount of classes
[tex]\left|\begin{array}{c|ccccc|c}x$(No of classes)& 1&2&3 &4&5&Sum\\x-\mu&-1.72&-0.72&0.28&1.28&2.28\\(x-\mu)^2&2.9584&0.5184&0.0784&1.6384&5.1984\\P(x)&0.24&0.26&0.12&0.3 &0.08\\--&--&---&---&--&--&--\\(x-\mu)^2P(x)&0.71&0.13&0.01&0.49&0.42&1.76\end{array}\right|[/tex]
Standard Deviation
[tex]=\sqrt{\sum(x-\mu)^2P(x)} \\=\sqrt{1.76} \\\sigma =1.33[/tex]