Answer:
Step-by-step explanation:
surface area=2×area of trapezoid(front and back)+area of base (rectangle)+area of top (area of two rectangles)+area of side rectangle
surface area=2[(8+6+8)/2×7]+(8+6)×6+(8+9)×6+7×6
=2×77+14×6+17×6+7×6
=154+84+102+42
=382 cm²
front is made of rectangle and a triangle.
together they make a trapezoid with parallel sides 14 (8+6) and 8
area of trapezoid=(sum of parallel sides)/2×length of perpendicular between parallel sides (here 7)
=(14+8)/2×7=77
area of two trapezoids (front and back)=2×77=154 cm²
base contains two rectangles (8×6 and 6×6)
area of base=8×6+6×6=48+36=84 cm²
Top contains two rectangles (8×6 and 9×6)
area of top=8×6+9×6=48+54=102 cm²
area of side rectangle=7×6=42 cm²
Total surface area=154+84+102+42=382 cm²
