Answer:
[tex]a = \frac{2(vt-d)}{t^{2} }[/tex]
Step-by-step explanation:
Given the formula for calculating the displacement of a body as shown below;
[tex]d = vt - \frac{1}{2} at^{2}[/tex]
d = displacement
v = final velocity
a = acceleration
t = time
To make the acceleration a the subject of the formula, the followin steps must be taken;
Step 1: Subtract vt from both sides of the equation
[tex]d-vt = vt-vt-\frac{1}{2}at^{2} \\ d-vt = -\frac{1}{2}at^{2}\\2(d-vt) = -at^{2}[/tex]
Step 2: Divide both sides by t²
[tex]\frac{2(d-vt)}{t^{2} } = \frac{-at^{2} }{t^{2} } \\a = \frac{-2(d-vt)}{t^{2} }[/tex]
[tex]a = \frac{2(vt-d)}{t^{2} }[/tex]