Answer:
89.01% probability that a flight arrives on time given that it departed on time.
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Departing on time
Event B: Arriving on time.
The probability that a flight departs and arrives on time is 0.81.
This means that [tex]P(A \cap B) = 0.81[/tex]
The probability that an airplane flight departs on time is 0.91.
This means that [tex]P(A) = 0.91[/tex]
Find the probability that a flight arrives on time given that it departed on time.
[tex]P(B|A) = \frac{0.81}{0.91} = 0.8901[/tex]
89.01% probability that a flight arrives on time given that it departed on time.