Respuesta :

Answer:

[tex] \boxed{\sf x = - \frac{13}{3}} [/tex]

Step-by-step explanation:

[tex] \sf Solve \: for \: x: \\ \sf \implies 6x + 7 = 3x - 6 \\ \\ \sf Subtract \: 3 x \: from \: both \: sides: \\ \sf \implies (6x - \boxed{3x}) + 7 = (3x - \boxed{3x}) - 6 \\ \\ \sf 6x - 3x = 3x : \\ \sf \implies \boxed{3x} + 7 = (3x - 3x) - 6 \\ \\ \sf 3x - 3x = 0 : \\ \sf \implies 3x + 7 = - 6 \\ \\ \sf Subtract \: 7 \: from \: both \: sides: \\ \sf \implies 3x + (7 - \boxed{7}) = - \boxed{7} - 6 \\ \\ \sf 7 - 7 = 0 : \\ \sf \implies 3x = - 7 - 6 \\ \\ \sf - 7 - 6 = - 13 : \\ \sf \implies 3x = - 13 \\ \\ \sf Divide \: both \: sides \: of \: 3x = - 13 \: by \: 3: \\ \sf \implies \frac{3x}{3} = - \frac{13}{3} \\ \\ \sf \frac{3}{3} = 1 : \\ \sf \implies x = - \frac{13}{3} [/tex]

Answer:

x = [tex]\frac{-13}{3}[/tex]

Step-by-step explanation:

=> 6x+7 = 3x-6

=> 6x-3x = -6-7

=> 3x = -13

Dividing both sides by 3

=> x = [tex]\frac{-13}{3}[/tex]

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