Answer:
Resistance of 8 feet wire = 0.81 Ω
Step-by-step explanation:
Equation representing the relation between the resistance and length of a cylindrical shaped wire is,
R = ρ.[tex]\frac{l}{A}[/tex]
Here R = Resistance of the cylindrical wire
ρ = Resistivity of the material
l = Length of the wire
A = Cross sectional area of the wire.
If length of the wire = 160 ft
Resistance = 16.2 Ω
By substituting these values in the formula,
16.2 = ρ.[tex]\frac{160}{A}[/tex]
ρ = [tex]\frac{16.2\times A}{160}[/tex]
Similarly, if length of the same wire = 8 ft
From the given formula,
R = ρ.[tex]\frac{8}{A}[/tex]
R = [tex]\frac{16.2\times A}{160}\times \frac{8}{A}[/tex]
= 0.81 Ω
Therefore, resistance of 8 feet wire will be 0.82 Ω.
