Answer:
Option A.
Step-by-step explanation:
The given function is
[tex]f(x)=\dfrac{5}{x^2}[/tex]
We need to find the range of the function f(x) on the domain [tex]-5\leq x\leq 5[/tex].
At x=-5,
[tex]f(-5)=\dfrac{5}{(-5)^2}=\dfrac{5}{25}=\dfrac{1}{5}[/tex]
At x=5,
[tex]f(5)=\dfrac{5}{(5)^2}=\dfrac{5}{25}=\dfrac{1}{5}[/tex]
As x approaches to 0, then the function approaches to positive infinity.
Draw the graph of given function as shown below.
In the graph x-axis represents the domain and y-axis represents the range.
From the graph it is clear that on the domain [tex]-5\leq x\leq 5[/tex] the value of function is greater than or equal to [tex]\dfrac{1}{5}[/tex].
So, range is [tex]f(x)\geq \dfrac{1}{5}.[/tex]
Therefore, the correct option is A.